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JCECE Medical JCECE Medical Solved Paper-2012

  • question_answer
    The resistance of 1 N solution of acetic acid is \[250\Omega ,\]when measured in a cell having a cell constant of \[\text{1}\text{.15}\,\text{c}{{\text{m}}^{-1}}.\]The equivalent  conductance \[({{\Omega }^{-1}}c{{m}^{2}}\,\text{equi}{{\text{v}}^{-1}})\] of 1 N acetic acid is    

    A)  2.3                

    B)  4.6

    C)  9.2               

    D)  18.4

    Correct Answer: A

    Solution :

     Equivalent conductivity \[({{\Lambda }_{eq}})=\frac{\kappa \times 1000}{c}\] \[\kappa =\frac{\text{cell}\,\text{constant}}{\text{resistance}}\] \[=\frac{1.15}{250}S\,c{{m}^{-1}}\] \[{{\Lambda }_{eq}}=\frac{1.15\times 1000}{250\times 1}\] \[=4.6\,{{\Omega }^{-1}}\text{c}{{\text{m}}^{\text{2}}}\,\text{equi}{{\text{v}}^{-1}}\]


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