A) acetic acid
B) saccharic acid
C) glyceraldehyde
D) gluconic acid
Correct Answer: A
Solution :
\[\underset{glu\cos e}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,+[O]\xrightarrow[{{H}_{2}}O]{B{{r}_{2}}}\underset{\text{gluconic}\,\text{acid}}{\mathop{C{{H}_{2}}OH{{(CHOH)}_{4}}COOH}}\,\]
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