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JCECE Medical JCECE Medical Solved Paper-2012

  • question_answer
    The magnetic moment of a transition metal ion is \[\sqrt{15}\,BM.\]Therefore, the number of unpaired electrons present in it is

    A)  4               

    B)  1

    C)  2               

    D)  3

    Correct Answer: A

    Solution :

     Magnetic moment \[=\sqrt{n(n+2)}\] where,\[n=\]number of unpaired electrons Given \[\mu =\sqrt{15}\] \[\sqrt{15}=\sqrt{n(n+2)}\] \[15=n(n+2)\] \[{{n}^{2}}+2n-15=0\] \[(n+5)(n-37)=0\] \[n=3\] \[(\because \,n\ne -5)\]


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