JCECE Medical JCECE Medical Solved Paper-2012

  • question_answer
    The radius of two metallic spheres A and B are  \[{{r}_{1}}\]and \[{{r}_{2}}\]respectively \[({{r}_{1}}>{{r}_{2}}).\] They are connected by a thin wire and the system is given a certain charge. The charge will be greater

    A)  equal on both

    B)  zero on both            

    C)  on the surface of sphere A

    D)  on the surface of sphere B

    Correct Answer: C

    Solution :

     When the spheres are connected by a wire, then potential on both becomes equal. \[\therefore \] \[\frac{{{Q}_{1}}}{{{r}_{1}}}=\frac{{{Q}_{2}}}{{{r}_{2}}}\]\[\Rightarrow \]\[\frac{{{Q}_{1}}}{{{Q}_{2}}}=\frac{{{r}_{1}}}{{{r}_{2}}}\] When \[{{r}_{1}}>{{r}_{2}},\]then \[{{Q}_{1}}>{{Q}_{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner