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JCECE Medical JCECE Medical Solved Paper-2011

  • question_answer
    Two pendulum have time period T and\[\frac{5T}{4}\] they start SHM at the same time form the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation

    A) \[{{45}^{o}}\]   

    B) \[{{90}^{o}}\]  

    C)  60°   

    D) \[~{{30}^{o}}\]

    Correct Answer: B

    Solution :

     When bigger pendulum of time period \[(5T/4)\]  completes one vibration, the smaller  pendulum will complete \[(5T/4)\] vibration. It means the smaller pendulum will be leading the bigger pendulum by phase\[\frac{T}{4}s=\frac{\pi }{2}rad={{90}^{o}}.\]


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