A) 2.5
B) 2.0
C) 1.5
D) 1
Correct Answer: B
Solution :
For acid-base reaction, \[\underset{\text{HCl}}{\mathop{\underset{\text{(acid)}}{\mathop{{{\text{N}}_{\text{1}}}{{\text{V}}_{\text{1}}}}}\,}}\,\text{=}\underset{\text{NaOH}}{\mathop{\underset{\text{(base)}}{\mathop{{{\text{N}}_{\text{2}}}{{\text{V}}_{\text{2}}}}}\,}}\,\] \[20\times {{N}_{1}}=40\times 0.005\] \[{{N}_{1}}=0.010=1\times {{10}^{-2}}\] \[pH=-\log [{{H}^{+}}]=-log(1\times {{10}^{-2}})=2.0\]
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