A) \[600\,\mu C,150\,V\]
B) \[300\,\mu C,75\,V\]
C) \[800\,\mu C,200\,V\]
D) \[580\,\mu C,145\,V\]
Correct Answer: D
Solution :
\[\frac{1}{C}=\frac{1}{20}+\frac{1}{8}+\frac{1}{12}\] \[\frac{1}{C}=\frac{6+15+10}{120}\] or \[C=\frac{120}{31}\mu F\] Now, \[Q=CV=\frac{120}{31}\times 300\mu C\] Charge across \[4\mu F\] \[=\frac{120\times 300}{31\times 2}=580.6\,\mu C\] Voltage across \[4\mu F\] \[=\frac{580.6}{4}V=145.15V\]
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