A) 150 kcal
B) 200 kcal
C) 250 kcal
D) 350 kcal
Correct Answer: B
Solution :
When 2.0 g\[\text{2}\text{.0}\left( \text{or}\,\frac{\text{2}}{\text{16}}\text{mol} \right)\] methane is burnt, heat evolved = 25 kcal. \[\therefore \]When 1 mol methane is burnt, heat evolved will be \[=\frac{25}{(2/16)}=\frac{25\times 16}{2}=200\,\text{kcal}\]
You need to login to perform this action.
You will be redirected in
3 sec
