A) \[N{{a}^{+}}\]
B) \[M{{g}^{2+}}\]
C) \[A{{l}^{3+}}\]
D) \[S{{i}^{4+}}\]
Correct Answer: D
Solution :
Ionic radii varies inversely-with nuclear charge. Higher the nuclear charge, smaller is the ionic radii. Since, \[\text{S}{{\text{i}}^{\text{4+}}}\]has the highest nuclear charge among the give, so it has lowest ionic radii.
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