A) \[{{K}_{2}}S{{O}_{4}}\]
B) \[NaHS{{O}_{4}}\]
C) Sugar
D) \[MgS{{O}_{4}}\]
Correct Answer: D
Solution :
\[i=2\]means two ions are present in the solution \[{{K}_{2}}S{{O}_{4}}\xrightarrow{{}}\underbrace{2{{K}^{+}}+SO_{4}^{2-}}_{3\,\text{ions}}\] \[NaHS{{O}_{4}}\xrightarrow{{}}\underbrace{N{{a}^{+}}+{{H}^{+}}+SO_{4}^{2-}}_{3\text{ions}}\] \[\text{Sugar}\xrightarrow[{}]{{}}\text{No}\,\text{ions}\] \[\text{MgS}{{\text{O}}_{4}}\xrightarrow{{}}\underbrace{M{{g}^{2+}}+SO_{4}^{2-}}_{\text{2}\,\text{ions}}\] Thus, vant Hoff factor is 2 for dilute solution of \[\text{MgS}{{\text{O}}_{\text{4}}}\text{.}\]
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