A) \[V=-(x+y)+\]constant
B) \[V=\text{constant}\]
C) \[V=-({{x}^{2}}+{{y}^{2}})+cons\tan t\]
D) \[V=-xy+\text{constant}\]
Correct Answer: D
Solution :
We know that \[dV=-E.dr\] \[=-(yi+xj).(idx+jdy+kdz)\] \[=-(ydx+nxdy)\] \[dv=-d(xy)\] Integrating both sides, we get \[V=-xy+\text{constant}\]
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