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JCECE Medical JCECE Medical Solved Paper-2011

  • question_answer
    An open pipe of length 33 cm resonates with frequency of 1000 Hz. If the speed of sound is \[333\,m{{s}^{-1}},\]then this frequency is

    A)  fundamental frequency of the pipe

    B)  third harmonic of the pipe

    C)  second harmonic of the pipe

    D)  fourth harmonic of the pipe      

    Correct Answer: C

    Solution :

     1000 Hz = Frequency of p th harmonic \[=\frac{pV}{2l}=\frac{p\times 330}{2\times 33}\] \[=\frac{p\times 330\times 100}{2\times 33}\] \[p=2\]


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