JCECE Medical JCECE Medical Solved Paper-2011

  • question_answer
    A body moving with uniform acceleration describes 12 m in the third second of its motion and 20 m in the 5th second. Find the velocity after 10 th second.

    A)  40 m/s          

    B)  42 m/s

    C)  52 m/s          

    D)  4m/s

    Correct Answer: B

    Solution :

     \[{{S}_{n}}=u+\frac{a}{2}(2n-1)\] \[12=u+\frac{a}{2}(2\times 3-1)\] ?(i) and \[20=u+\frac{a}{2}(2\times 5-1)\] ?(ii) Subtract Eq. (i) from Eq. (ii) \[8=\frac{a}{2}(9-5)=2a\] \[\Rightarrow \] \[a=4m/{{s}^{2}}\] From Eq. (i) \[12=u+\frac{4}{2}\times 5\] \[u=2\,m/s\] Velocity \[v=u+at=2+4\times 10\] \[=42\,m/s\]


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