A) \[3\times {{10}^{4}}N\]
B) \[3\times {{10}^{2}}N\]
C) \[3\times {{10}^{-2}}N\]
D) \[3\times {{10}^{-4}}N\]
Correct Answer: C
Solution :
Force, \[F=Bil\,\sin \,\theta \] \[=500\times {{10}^{-4}}\times 3\times (40\times {{10}^{-2}})\times \frac{1}{2}\] \[=3\times {{10}^{-2}}N\]
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