question_answer

To get an output 1 from the circuit shown in the figure, the input must be

A)  \[A=0,B=1,C=0\]

B)  \[A=1,B=0,C=0\]

C)  \[A=1,B=0,C=1\]

D)  \[A=1,B=1,C=0\]

Correct Answer: C

Solution :

 We can realize the gate circuit as Output of gate \[1,{{Y}_{1}}=A+B\] Output of gate\[1,{{Y}_{2}}={{Y}_{1}}.C\] \[=(A+B).C\]  If \[A=0,B=1,C=0,\]then \[{{Y}_{2}}=(0+1).0=1.0=0\]  If \[A=1,B=0,C=0,\]then \[{{Y}_{2}}=(1+0).0=1.0=0\]  If \[A=1,B=0,C=1,\]then \[{{Y}_{2}}=(1+0).1=1.1=1\]  If \[A=I,B=1,C=0,\]then \[{{Y}_{2}}=(1+1).0=1.0=0\]