JCECE Medical JCECE Medical Solved Paper-2010

  • question_answer
    The contribution in the total current flowing through a semiconductor due to electrons  and holes are\[\frac{3}{4}\]and \[\frac{1}{4}\] respectively. If the  drift velocity of electrons is \[\frac{5}{2}\] times that of holes at this temperature, then the ratio of concentration of electrons and holes is

    A)  6:5            

    B)  5:6

    C)  3:2            

    D)  2:3

    Correct Answer: A

    Solution :

     As we know, current density \[J=nqv\] \[\Rightarrow \] \[{{J}_{e}}={{n}_{e}}q{{v}_{e}}\] and \[{{J}_{h}}={{n}_{^{h}}}q{{v}_{h}}\] \[\Rightarrow \] \[\frac{{{J}_{e}}}{{{J}_{h}}}=\frac{{{n}_{e}}}{{{n}_{^{h}}}}\times \frac{{{v}_{e}}}{{{v}_{h}}}\] \[\Rightarrow \] \[\frac{3/4}{1/4}=\frac{{{n}_{e}}}{{{n}_{h}}}\times \frac{5}{2}\] \[\Rightarrow \] \[\frac{{{n}_{e}}}{{{n}_{h}}}=\frac{6}{5}\]


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