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JCECE Medical JCECE Medical Solved Paper-2010

  • question_answer
    A 50 turns circular coil has a radius of 3 cm, it is kept in a magnetic field acting normal to the area of the coil. The magnetic field B increased from 0.10 T to 0.35 T in 2 millisecond. The average induced emf in the coil is

    A)  1.77 V          

    B)  17.7 V

    C) 177 V           

    D)  0.177 V

    Correct Answer: B

    Solution :

     Induced emf \[e=\frac{-NA({{B}_{2}}-{{B}_{1}})cos\theta }{\Delta t}\] \[=\frac{50\times \pi \times {{(30\times {{10}^{-2}})}^{2}}[0.35-0.10]cos{{0}^{o}}}{2\times {{10}^{-3}}}\] \[\Rightarrow \] \[=17.7\,V\]


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