A) 392
B) 31.6
C) 278
D) 156
Correct Answer: A
Solution :
Mohrs salt is \[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}.FeS{{O}_{4}}.6{{H}_{2}}O.\] The equation is: \[5F{{e}^{2+}}+MnO_{2}^{-}+8{{H}^{+}}\xrightarrow{{}}\]= \[5F{{e}^{3+}}+M{{n}^{2+}}+4{{H}_{2}}O\] Total change in oxidation number of iron \[=\,(+\,3)-(+2)\] \[=+\,1\] So, equivalent wt. of Mohrs salt \[\text{=}\frac{\text{mol}\text{.wt}\text{.of}\,\text{Mohr }\!\!\!\!\text{ s}\,\text{salt}}{\text{1}}\] \[\text{=}\frac{392}{1}\] \[=392\]
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