A) anhydrous \[AlC{{l}_{3}}\]
B) \[FeC{{l}_{3}}\]
C) anhydrous\[ZnC{{l}_{2}}\]
D) Cu
Correct Answer: C
Solution :
\[-\text{OH}\]group is converted into \[-\text{Cl}\]group by \[\text{SOC}{{\text{l}}_{\text{2}}}\]or anhy \[ZnC{{l}_{2}}/\text{conc}\,\text{HCl}\]or \[\text{HCl}\]etc.
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