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JCECE Medical JCECE Medical Solved Paper-2009

  • question_answer
    Solubility product of a salt AB is \[1\times {{10}^{-8}}{{M}^{2}}\,\]in a solution in which the concentration of \[{{A}^{+}}\]ions is \[{{10}^{-3}}\,M.\]The salt will precipitate when the concentration of \[{{B}^{-}}\]ions is kept

    A)  between \[{{10}^{-8}}\,M\]to \[{{10}^{-7}}\,M\]

    B)  between \[{{10}^{-7}}M\]to \[{{10}^{-8}}M\]

    C)  \[>{{10}^{-5}}M\]

    D)  \[<{{10}^{-8}}M\]

    Correct Answer: C

    Solution :

     A salt is precipitated only when the product of ionic concentration is more than its solubility product. \[{{K}_{sp}}=1\times {{10}^{-8}}\] \[[{{A}^{+}}]={{10}^{-3}}M\] \[[{{B}^{-}}]=\frac{1\times {{10}^{-5}}}{{{10}^{-3}}}={{10}^{-5}}\,M\] So, AB will be precipitated only when the concentration of \[[{{B}^{-}}]\] is more than \[{{10}^{-5}}\,M.\]


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