A) \[\text{zero to}+5\]
B) \[+\,1\,\text{to}\,\text{+}\,\text{5}\]
C) \[\text{ }\!\!~\!\!\text{ zero to}-3\]
D) \[~+\,2\text{ to}+5\]
Correct Answer: A
Solution :
Bromine has zero oxidation state because it is in free state \[\overset{0}{\mathop{B{{r}_{2}}}}\,\xrightarrow{{}}BrO_{3}^{-}\] \[BrO_{3}^{-}\] \[x+(-2\times 3)=-1\] \[x+(-6)=-1\] \[x=+\,6-1\] \[=+\,5\] So, oxidation number changes from 0 to \[+\,5.\]
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