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JCECE Medical JCECE Medical Solved Paper-2009

  • question_answer
    A wire PQR is bent as shown in figure and is placed in a region of uniform magnetic field B. The length of\[PQ=QR=l.A\] current \[I\] ampere flows through the wire as shown. The  agnitude of the force on PQ and QR will be

    A)  \[BIl,0\]

    B)  \[2BIl,0\]

    C)  \[0,BIl\]

    D)  \[0,0\]

    Correct Answer: C

    Solution :

     The Lorentz force acting on the current carrying conductor in the magnetic field is \[F=IBl\,\sin \theta \] Since, wire PQ is parallel to the direction of magnetic field, then \[\theta =0,\] \[\therefore \] \[{{F}_{PQ}}=IBl\sin {{0}^{o}}=0\] Also, wire QR is perpendicular to the direction of magnetic field, then \[\theta ={{90}^{o}}.\] \[\therefore \] \[{{F}_{QR}}=IBl\sin {{90}^{o}}=IBl\]


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