question_answer

In a set of the given reactions, acetic acid yielded a product C. \[C{{H}_{3}}COOH+PC{{l}_{5}}\xrightarrow{{}}A\] \[\text{A}\xrightarrow[\text{anhy}\,\text{AlC}{{\text{l}}_{\text{3}}}]{{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}}\text{B}\xrightarrow[\text{ether}]{{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{MgBr}}\text{C}\] Product C would be

A)  \[C{{H}_{3}}CH(OH){{C}_{6}}{{H}_{5}}\]

B)  \[C{{H}_{3}}-\overset{{{C}_{2}}{{H}_{5}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,(OH){{C}_{6}}{{H}_{5}}\]

C)  \[C{{H}_{3}}CH(OH){{C}_{2}}{{H}_{5}}\]

D)  \[C{{H}_{3}}CO{{C}_{6}}{{H}_{5}}\]

Correct Answer: B

Solution :

 \[C{{H}_{3}}COOH+PC{{l}_{5}}\xrightarrow{{}}\underset{(A)}{\mathop{C{{H}_{3}}COCl}}\,\]