A) Acetone
B) Acetic acid
C) Acetonitrile
D) Acetamide
Correct Answer: C
Solution :
[a]\[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{O}{\mathop{\underset{s{{p}^{2}}}{\overset{||}{\mathop{C}}}\,}}\,-\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\] [b] \[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{O}{\mathop{\underset{s{{p}^{2}}}{\overset{||}{\mathop{C}}}\,}}\,-OH\] [c] \[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\underset{sp}{\mathop{C}}\,\equiv N\] [d] \[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{O}{\mathop{\underset{s{{p}^{2}}}{\overset{||}{\mathop{C}}}\,}}\,-N{{H}_{2}}\] Acetonitrile does not contain\[s{{p}^{2}}-\]hybridized carbon.
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