A) \[5.49\,\,\times \,\,{{10}^{1}}C\] of electricity
B) \[5.49\,\,\times \,\,{{10}^{4}}C\]of electricity
C) \[1.83\times {{10}^{7}}C\]of electricity
D) \[5.49\times {{10}^{7}}C\]of electricity
Correct Answer: D
Solution :
\[A{{l}^{3+}}+3{{e}^{-}}\xrightarrow{{}}Al\] \[w=zQ\] where, \[w=\]amount of metal \[w=5.12\,kg=5.12\times {{10}^{3}}g\] \[z=\]electrochemical equivalent \[z=\frac{\text{Equivalent}\,\text{weight}}{\text{96500}}=\frac{\text{Atomic}\,\text{mass}}{\text{Electrons}\,\text{ }\!\!\times\!\!\text{ }\,\text{96500}}\] \[z=\frac{27}{3\times 96500}\] \[5.12\times {{10}^{3}}=\frac{27}{3\times 96500}\times Q\] \[Q=\frac{5.12\times {{10}^{3}}\times 3\times 96500}{27}C\] \[=5.49\times {{10}^{7}}C\]
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