A) 140 Torr
B) 20 Torr
C) 68 Torr
D) 72 Torr
Correct Answer: D
Solution :
Mole fraction of \[P=\frac{3}{3+2}=\frac{3}{5}\] Mole fraction of Q\[Q=\frac{2}{3+2}=\frac{2}{5}\] Hence, total vapour pressure = Mole fraction of \[\text{P}\,\text{ }\!\!\times\!\!\text{ }\,\text{V}\text{.P}\text{.}\]of P + mole fraction of \[Q\,\,\text{ }\!\!\times\!\!\text{ }\,\text{V}\text{.P}\text{.}\]of Q \[=\left( \frac{3}{5}\times 80+\frac{2}{5}\times 60 \right)=48+24\] \[=72\,\text{Torr}\]
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