A) 294 g
B) 127g
C) 49 g
D) 24.5 g
Correct Answer: C
Solution :
\[C{{r}_{2}}O_{7}^{2-}+14{{H}^{+}}+6{{e}^{-}}\xrightarrow{{}}2C{{r}^{3+}}+7{{H}_{2}}O\] Gram eq. wt. \[=\frac{\text{Gram}\,\text{molecular}\,\text{weight}}{\begin{align} & \text{Change}\,\text{in}\,\text{oxidation}\,\text{number} \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{per}\,\text{atom} \\ \end{align}}\]\[\text{Gram}\,\text{eq}\text{.wt}\text{.=}\frac{294}{6}\] \[=49\,g\]
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