JCECE Medical JCECE Medical Solved Paper-2008

  • question_answer
    If a rubber ball is taken at the depth of 200m in a pool, its volume decreases by 0.1%. If the density of water is \[\text{1 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{3}}}\,\text{kg/}{{\text{m}}^{\text{3}}}\]and \[g=10\,m/{{s}^{2}},\]then the volume of elasticity in \[\text{N/}{{\text{m}}^{\text{2}}}\]will be

    A) \[\text{1}{{\text{0}}^{8}}\]           

    B) \[\text{2}\times \text{1}{{\text{0}}^{8}}\]

    C) \[\text{1}{{\text{0}}^{9}}\]           

    D) \[\text{2}\times \text{1}{{\text{0}}^{9}}\]

    Correct Answer: D

    Solution :

     \[K=\frac{\Delta p}{\Delta V/V}=\frac{\rho hg}{\Delta V/V}\] \[=\frac{200\times {{10}^{3}}\times 10}{0.1/100}\] \[=2\times {{10}^{9}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner