A) \[n-\]propyl alcohol
B) isopropyl alcohol
C) acetaldehyde
D) acetone
Correct Answer: C
Solution :
\[H-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O{{C}_{2}}{{H}_{5}}+C{{H}_{3}}MgBr\to H-\underset{\underset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\downarrow {{H}_{2}}O}{\mathop{O{{C}_{2}}{{H}_{5}}}}\,}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-OMgBr\] \[C{{H}_{3}}CHO\xleftarrow[-{{H}_{2}}O]{}H-\underset{OH}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-OH\]
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