JCECE Medical JCECE Medical Solved Paper-2007

  • question_answer
    The change in entropy for the fusion of 1 mole of ice is [\[\text{mp}\,\text{of}\,\text{ice}\,\,\text{=}\,\,\text{273}\,\text{K,}\], molar enthalpy of fusion for ice\[=\,\,6.0\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\]]

    A) \[11.73\,J{{K}^{-1}}\,mo{{l}^{-1}}\]

    B)  \[18.84\,J{{K}^{-1}}\,mo{{l}^{-1}}\]

    C)  \[21.97\,J{{K}^{-1}}\,mo{{l}^{-1}}\]

    D)  \[24.47\,J{{K}^{-1}}\,mo{{l}^{-1}}\]

    Correct Answer: C

    Solution :

     Entropy change of fusion \[\Delta {{S}_{f}}=\frac{\Delta {{H}_{f}}}{T}\] \[\Delta {{H}_{f}}=60\times {{10}^{3}}\,J\,mo{{l}^{-1}},T=273\,K\] \[\Delta {{S}_{f}}=\frac{60\times {{10}^{3}}}{273}\] \[=21.97\,J\,K{{\,}^{-1}}\,mo{{l}^{-1}}\]


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