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JCECE Medical JCECE Medical Solved Paper-2007

  • question_answer
    Oxidation number of Fe in\[\text{F}{{\text{e}}_{\text{2}}}{{\text{O}}_{\text{3}}}\] is

    A) \[\frac{1}{2}\]

    B)  \[\frac{2}{6}\]

    C)  \[\frac{8}{3}\]

    D)  \[\frac{3}{2}\]

    Correct Answer: C

    Solution :

     Let the oxidation number of Fe in \[\text{F}{{\text{e}}_{\text{3}}}{{\text{O}}_{\text{4}}}\]is \[x.\] Hence,   \[3x+4(-2)=0\] \[3x+(-8)=0\] \[3x=8\] \[x=\frac{8}{3}\]


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