A) 2.5
B) 3
C) 5
D) 7.5
Correct Answer: B
Solution :
\[\underset{=\,36\,g}{\mathop{\underset{2\,\,\times \,18\,}{\mathop{\underset{2\,\text{mole}}{\mathop{2{{H}_{2}}O}}\,}}\,}}\,\xrightarrow{\text{Electrolysis}}2{{H}_{2}}+\underset{1\,\text{mole}}{\mathop{{{O}_{2}}}}\,\] \[\because \]\[36\,g\]of \[{{\text{H}}_{\text{2}}}\text{O}\]produce 1 mole of oxygen. \[\therefore \]108 g of water will produce oxygen. \[=\frac{108}{36}=3\,mol\]
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