JCECE Medical JCECE Medical Solved Paper-2007

  • question_answer
    The time of reverberation of a room A is one second. What will be the time (in seconds) of reverberation of a room, having all the dimensions double of those of room A?

    A)  2

    B)  4

    C)  \[\frac{1}{2}\]

    D)  1

    Correct Answer: A

    Solution :

     Sabine formula for reverberation time is \[T=\frac{0.16\,V}{\sum{aS}}\] where V is volume of hall in \[{{m}^{3}}.\] \[\sum{aS}={{a}_{1}}{{S}_{1}}+{{a}_{2}}{{S}_{2}}+...\] = total absorption of the hall (room) Here, \[{{S}_{1}},{{S}_{2}},{{S}_{3}}.....\]are surface areas of the absorbers   and  \[{{a}_{1}},{{a}_{2}},{{a}_{3}}.....\]  are   their respective absorption coefficients. \[\therefore \] \[\frac{T}{T}=\frac{V}{S}\times \frac{S}{V}=\frac{{{(2)}^{3}}}{{{(2)}^{2}}}=\frac{8}{4}=2\] Hence, \[T=2T=2\times 1=2\,S\]


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