A) 64 g
B) 16 g
C) 32 g
D) 8 g
Correct Answer: A
Solution :
If \[{{r}_{x}}=r\]then \[{{r}_{C{{H}_{4}}}}=2r\] \[{{M}_{C{{H}_{4}}}}=12+4=16\] \[{{M}_{x}}=?\] We know that, \[\frac{{{r}_{C{{H}_{4}}}}}{{{r}_{x}}}=\sqrt{\frac{{{M}_{x}}}{{{M}_{C{{H}_{4}}}}}}\] \[\frac{2r}{r}=\sqrt{\frac{{{M}_{x}}}{16}}\] \[{{(2)}^{2}}=\frac{{{M}_{x}}}{16}\] \[4=\frac{{{M}_{x}}}{16}\] or \[{{M}_{x}}=64\]
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