A) less at \[{{T}_{1}}\]
B) more at \[{{T}_{1}}\]
C) equally in the two cases
D) cannot say
Correct Answer: A
Solution :
From Weins displacement law \[{{\lambda }_{m}}T=\text{constant}\] ...(i) where\[{{\lambda }_{m}}\]corresponds to maximum wavelength, T is absolute temperature. Also, \[v=n\lambda \] ...(ii) where\[v\]is velocity,\[n\]the frequency,\[\lambda \] the wavelength. From Eqs. (i) and (ii), we get \[\frac{v}{n}.T=\text{constant}\] Given \[{{T}_{1}}<{{T}_{2}},\] hence frequency corresponding to maximum intensity is less at \[{{T}_{1}}.\]
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