A) \[~A{{g}_{2}}S{{O}_{4}}\]
B) \[CuS{{O}_{4}}\]
C) \[~PbS{{O}_{4}}\]
D) \[~CdS{{O}_{4}}\]
Correct Answer: B
Solution :
\[\text{CuS}{{\text{O}}_{\text{4}}}\]reacts with \[\text{KI}\]to give \[{{\text{I}}_{2}}\] as: \[2CuS{{O}_{4}}+4KI\xrightarrow{{}}2CuI+{{K}_{2}}S{{O}_{4}}+{{I}_{2}}\]
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