question_answer

In \[\text{S}{{\text{O}}_{\text{2}}}\]hybridisation is:

A) \[sp\]

B) \[s{{p}^{3}}\]

C) \[ds{{p}^{2}}\]

D) \[s{{p}^{2}}\]

Correct Answer: D

Solution :

 S(excited state)= It has two bonds and one lone pair The\[S-O\]) double bond arise from \[p\pi -d\pi \]bonding due to lateral overlap of p-orbitals of oxygen with \[d-\]orbitals of sulphur. The bond between S and O results from \[s{{p}^{2}}\]hybridization in S-atom.