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JCECE Medical JCECE Medical Solved Paper-2005

  • question_answer
    An adulterated sample of milk has a density of \[1032\,kg-{{m}^{3}},\] while pure milk has a density of \[1080\,kg-{{m}^{-3}}.\]The volume of pure milk in a sample of 10 L of adulterated milk is:

    A)  0.5 L           

    B)  1.0 L

    C)  2.0 L           

    D)  4.0 L

    Correct Answer: D

    Solution :

     Mass of adulterated milk \[{{M}_{A}}=1032\times 10\times {{10}^{-3}}=10.32\,kg\] Mass of water \[={{\rho }_{w}}{{V}_{w}}={{M}_{A}}-{{M}_{P}}\] \[\Rightarrow \]\[{{10}^{3}}(10\times {{10}^{3}}-{{V}_{P}})=10.32-1080\,{{V}_{P}}\] \[\Rightarrow \]\[10-{{10}^{3}}{{V}_{P}}=10.32-1080{{V}_{P}}\] \[\Rightarrow \]\[80{{V}_{P}}=0.32\] \[\Rightarrow \]\[{{V}_{P}}=\frac{0.32}{80}\times 1000=4L\]


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