A) 2 molar
B) 2 molal
C) 1 normal
D) 1 molal
E)
Correct Answer: B
Solution :
Key Idea: \[\text{Molality}\,\,\text{=}\,\frac{\text{moles}\,\text{of}\,\text{solute}}{\text{massof}\,\text{solvent}\,\text{in}\,\text{kg}}\] \[\text{=}\,\frac{\text{mass}\,\text{of}\,\text{solute/molecular}\,\text{weight}}{\text{mass}\,\text{of}\,\text{solvent}\,\text{in}\,\text{kg}}\] Given mass of solute\[~=117\text{ }g,\] molecular mass of \[\text{NaCl}\,\text{=}\,\text{58}\text{.5}\] mass of solvent \[=1000\text{ }g=1\text{ }kg\] \[\text{molality}=\frac{117/58.5}{1}\] \[=2\]
You need to login to perform this action.
You will be redirected in
3 sec
