A) \[(2\pi _{\pi }^{*}){{(2{{\pi }_{y}})}^{1}}\]
B) \[{{({{\pi }^{*}}2{{p}_{y}})}^{1}}({{\pi }^{*}}2p_{z}^{1})\]
C) \[{{(2\sigma _{s}^{*})}^{1}}{{(2{{\pi }_{y}})}^{1}}\]
D) \[{{(2\sigma _{s}^{*})}^{1}}{{(2{{\pi }_{y}})}^{1}}\]
Correct Answer: B
Solution :
Key Idea: Write configuration of oxygen according to molecular orbital theory \[{{O}_{2}}=16=\sigma 1{{s}^{2}},\sigma {{1}^{*}}{{s}^{2}},\sigma 2{{s}^{2}},{{\sigma }^{*}}2{{s}^{2}},\sigma 2{{p}_{x}}^{2},\] \[\pi 2{{p}_{y}}^{2},\pi 2{{p}_{z}}^{2},{{\pi }^{*}}2{{p}_{y}}^{1},{{\pi }^{*}}2{{p}_{z}}^{1}\] \[\therefore \]It has two unpaired electrons. \[\therefore \] \[{{\text{O}}_{\text{2}}}\] is paramagnetic.
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