JCECE Medical JCECE Medical Solved Paper-2005

  • question_answer
    The distance travelled by a sound wave when a tuning fork completes 25 vibrations is 16.5 m. If the frequency of the tuning fork is 500 Hz, find the velocity of sound.

    A) \[350\,m{{s}^{-1}}\]

    B)  \[330\,m{{s}^{-1}}\]

    C)  \[300\,m{{s}^{-1}}\]

    D)  \[450\,m{{s}^{-1}}\]

    Correct Answer: B

    Solution :

     Key Idea: \[Frequecy=\frac{1}{Time-period}\] The relation between velocity \[(v),\] and wavelength \[(\lambda )\] is given by \[v=n\lambda \] where,    \[n=\frac{1}{T}\] Given,  \[\lambda =\frac{16.5}{25}m,T=\frac{1}{500}s\] Hence, \[v=\frac{\lambda }{T}=\frac{16.5}{25}\times 500=330\,m{{s}^{-1}}\]


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