A) \[NaCl\]
B) \[CuCl\]
C) \[CuC{{l}_{2}}\]
D) \[CsCl\]
Correct Answer: C
Solution :
Key Idea: (i) More the covalent character, less is boiling point, (ii) Smaller the size of cation, more is polarizing power and more is covalent character, Among \[N{{a}^{+}}(of\,NaCl),C{{u}^{+}}(of\,CuCl),\]\[C{{u}^{2+}}(of\,CuC{{l}_{2}})\]and \[C{{s}^{+}}(of\,CsCl)\,size\,of\,C{{u}^{2+}}\]is smallest. \[\therefore \]\[\text{CuC}{{\text{l}}_{\text{2}}}\] has highest covalent character.
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