A) \[{{S}_{N}}1\] mechanism
B) \[{{S}_{N}}2\] mechanism
C) any of [a] and [b]
D) none of the above
Correct Answer: A
Solution :
Key Idea: [c] (i) Alkyl halides undergo, nucleophilic substitution. (ii)\[{{\text{3}}^{\text{o}}}\]alkyl halides undergo\[{{\text{S}}_{\text{N}}}\text{2}\]reaction mechanism. (iii) \[{{\text{1}}^{\text{o}}}\]alkyl halides undergo\[{{\text{S}}_{\text{N}}}\text{1}\]reaction mechanism. \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-Cl({{3}^{o}}-\text{butyl}\,\text{chloride})\] It is \[{{\text{3}}^{\text{o}}}\] alkyl halide, so it will undergo \[{{\text{S}}_{\text{N}}}\text{1}\]reaction mechanism. \[{{\text{S}}_{\text{N}}}\text{1}\]mechanism: \[{{H}_{3}}C-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-Cl\xrightarrow[-\text{C}{{\text{l}}^{-}}]{\text{Slow}}{{(C{{H}_{3}})}_{3}}{{C}^{+}}\] \[\xrightarrow[\text{fast}]{+O{{H}^{-}}}{{(C{{H}_{3}})}_{3}}C-OH\]
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