A) \[s{{p}^{2}}\]
B) \[s{{p}^{3}}{{d}^{2}}\]
C) \[s{{p}^{3}}\]
D) \[sp\]
Correct Answer: A
Solution :
Key Idea: Hybridisation \[=\frac{1}{2}\] [number of valence \[{{e}^{-}}\]in central atom + number of monovalent atoms - charge on cation + charge on onion] For \[S{{O}_{2}}\] Hybridisation\[=\frac{1}{2}(6+0-0+0)\] \[=3\] \[s{{p}^{2}}-\text{hybridisation}\text{.}\]
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