question_answer

A fireman wants to slide down a rope. The breaking load for the rope is\[\frac{\text{3}}{\text{4}}\text{th}\] of the weight of the man. With what acceleration should the fireman slide down? (Acceleration due to gravity is g)

A)  \[\frac{g}{2}\]

B)  \[\frac{g}{4}\]

C)  \[\frac{3g}{4}\]

D)  zero

Correct Answer: B

Solution :

 Let the resultant acceleration of fireman be a then                         \[R=mg-ma\] Given, \[R=\frac{3}{4}mg\] \[\therefore \] \[\frac{3}{4}mg=mg-ma\] \[\Rightarrow \] \[a=\frac{g}{4}\]