A) \[\pi /4\]
B) \[3\pi /5\]
C) \[\pi /6\]
D) \[\pi /=2\]
Correct Answer: C
Solution :
The phase of particle at \[t=3\,s\]is \[\text{o }\!\!|\!\!\text{ =}\omega \text{t=}\left( \frac{2\pi }{T} \right)t\] \[=\frac{2\pi \times 3}{12}=\frac{\pi }{2}\] At \[t=4s\] \[\text{o }\!\!|\!\!\text{ =}\omega t=\left( \frac{2\pi }{T} \right)t\] \[=\frac{2\pi \times 4}{12}=\frac{2\pi }{3}\] Phase difference \[\Delta \text{o }\!\!|\!\!\text{ =}\,\text{o}{{\text{ }\!\!|\!\!\text{ }}_{2}}-\text{o}{{\text{ }\!\!|\!\!\text{ }}_{1}}=\frac{2\pi }{3}-\frac{\pi }{2}=\frac{\pi }{6}\]
You need to login to perform this action.
You will be redirected in
3 sec
