A) oxidation of Sn
B) reduction of \[\text{HgC}{{\text{l}}_{\text{2}}}\]
C) formation of amalgum
D) oxidation of Hg
Correct Answer: B
Solution :
Key Idea: Write the equation to find composition of black colour. \[2HgC{{l}_{2}}+SnC{{l}_{2}}\xrightarrow{{}}H{{g}_{2}}C{{l}_{2}}+SnC{{l}_{4}}\] \[H{{g}_{2}}C{{l}_{2}}+SnC{{l}_{2}}\xrightarrow{{}}\underset{\text{black}}{\mathop{2Hg}}\,+Snl{{C}_{4}}\] \[\therefore \]Reduction of \[\text{HgC}{{\text{l}}_{\text{2}}}\]to Hg results in formation of black coloured mercury.
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