A) become four times
B) become half
C) become two times
D) remain unchanged
Correct Answer: B
Solution :
Momentum of a particle is related to de- Broglie wavelength through the relation given by \[p=\frac{h}{\lambda }\] where \[h\]is Plancks constant. or \[\lambda =\frac{h}{P}\] or \[\lambda \propto \frac{1}{P}\] i.e., de-Broglie wavelength is inversely proportional to the momentum of the particle, so, if momentum is doubled, then de-Broglie wavelength will become half.
You need to login to perform this action.
You will be redirected in
3 sec
