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JCECE Medical JCECE Medical Solved Paper-2003

  • question_answer
    The latent heat of vaporisation of water is \[\text{2250}\,\text{J/kg}\text{.}\]If the work done in the process of vaporisation of 1 kg is 168 J, then increase in internal energy will be:

    A)  1904 J        

    B)  1984 J

    C)  3202 J        

    D)  2082 J

    Correct Answer: D

    Solution :

     Heat supplied to vaporise the water \[dQ=mL\] where L is the latent heat of vaporisation of water. \[\therefore \] \[dQ=1\times 2250=2250\,J\] According to first law of thermodynamics, \[dQ=dU+dW\] or \[2250=dU+dW\] or \[dU=2250-168\] \[=2082\,J\]


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