A) \[{{H}_{2}}O\]
B) \[AlC{{l}_{3}}\]
C) \[RN{{H}_{2}}\]
D) \[N{{H}_{3}}\]
Correct Answer: B
Solution :
Key Idea: Electron acceptors are Lewis acid (i)\[{{\text{H}}_{\text{2}}}\overset{\centerdot \,\centerdot }{\mathop{\text{O}}}\,,R-\overset{\centerdot \,\centerdot }{\mathop{N}}\,{{H}_{2}}\]and \[\overset{\centerdot \,\centerdot }{\mathop{N}}\,{{H}_{3}}\] are electron donors and Lewis acid. (ii) \[\text{AlC}{{\text{l}}_{\text{3}}}\]is electron deficient compound and is electron acceptor. So it is Lewis acid.
You need to login to perform this action.
You will be redirected in
3 sec
